4z^2-24z+29=0

Solution for 4z^2-24z+29=0 equation:

4z^2-24z+29=0

a = 4; b = -24; c = +29;
Δ = b2-4ac
Δ = -242-4·4·29
Δ = 112
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{112}=\sqrt{16*7}=\sqrt{16}*\sqrt{7}=4\sqrt{7}$
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-4\sqrt{7}}{2*4}=\frac{24-4\sqrt{7}}{8}
$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+4\sqrt{7}}{2*4}=\frac{24+4\sqrt{7}}{8}
$